Question

Reduce the following equation into intercept form and find their intercepts on the axes.

 3x + 2y – 12 = 0

Answer 1

The given equation is 3x + 2y – 12 = 0.

It can be written as

3x + 2y – 12

`(3"x")/12 + (2"y")/12 = 1`

i.e. `"x"/4 + "y"/6 = 1` ..........(1)

This equation is of the form `"x"/"a" +"y"/"b" = 1`, where a = 4 and b = 6.

Therefore, equation (1) is in the intercept form, where the intercepts on the x and y axes are 4 and 6 respectively.