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Rationalise the denominator: 8/(sqrt(7) + sqrt(3) - Mathematics

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Question

Rationalise the denominator:

`8/(sqrt(7) + sqrt(3)`

Sum
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Solution

We are asked to rationalise the denominator `8/(sqrt(7) + sqrt(3)`

Step 1: Multiply numerator and denominator by the conjugate of the denominator:

`8/(sqrt(7) + sqrt(3)) xx (sqrt(7) - sqrt(3))/(sqrt(7) - sqrt(3))`

= `(8(sqrt(7) - sqrt(3)))/((sqrt(7) + sqrt(3))(sqrt(7) - sqrt(3))`

Step 2: Simplify denominator using identity (a + b)(a – b) = a2 – b2:

`sqrt(7)^2 - sqrt(3)^2`

= 7 – 3

= 4

Step 3: Final expression:

`(8(sqrt(7) - sqrt(3)))/4`

= `2(sqrt(7) - sqrt(3))`

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Chapter 1: Rational and Irrational Numbers - MISCELLANEOUS EXERCISE [Page 17]

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B Nirmala Shastry Mathematics [English] Class 9 ICSE
Chapter 1 Rational and Irrational Numbers
MISCELLANEOUS EXERCISE | Q 4. (vi) | Page 17
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