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प्रश्न
Rationalise the denominator:
`8/(sqrt(7) + sqrt(3)`
योग
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उत्तर
We are asked to rationalise the denominator `8/(sqrt(7) + sqrt(3)`
Step 1: Multiply numerator and denominator by the conjugate of the denominator:
`8/(sqrt(7) + sqrt(3)) xx (sqrt(7) - sqrt(3))/(sqrt(7) - sqrt(3))`
= `(8(sqrt(7) - sqrt(3)))/((sqrt(7) + sqrt(3))(sqrt(7) - sqrt(3))`
Step 2: Simplify denominator using identity (a + b)(a – b) = a2 – b2:
`sqrt(7)^2 - sqrt(3)^2`
= 7 – 3
= 4
Step 3: Final expression:
`(8(sqrt(7) - sqrt(3)))/4`
= `2(sqrt(7) - sqrt(3))`
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अध्याय 1: Rational and Irrational Numbers - MISCELLANEOUS EXERCISE [पृष्ठ १७]
