Advertisements
Advertisements
Question
Ratio of the distance of the school from A’s home to the distance of the school from B’s home is 2 : 1.
(i) Who lives nearer to the school?
(ii) Complete the following table:
Advertisements
Solution
Ratio of the distance of the school from A’s home to the distance of the school from B’s hence = 2 : 1
(i) B lives nearest to the school
(ii) Let A’s home is 2x km from school and B’s home is x km
Distance of school from A’s home = 2 x Distance of school from B’s home
⇒ If A lives at a distance of 4 km, then B lives at a distance of = `1/2xx4` = 2 km
⇒ If B lives at a distance of 9 km then A lives at a distance of = 2 × 9 = 18 km
⇒ If A lives at a distance of 8 km then B lives at a distance =`1/2xx8` = 4 km
⇒ If B lives at a distance of 8 km, then A lives at a distance = 2 × 8 = 16 km
⇒ If A lives at a distance of 6 km, then B lives at a distance = `1/2xx6` = 3 km
APPEARS IN
RELATED QUESTIONS
If (3x – 9) : (5x + 4) is the triplicate ratio of 3 : 4, find the value of x.
if `x/a = y/b = z/c` prove that `(ax - by)/((a + b)(x - y)) + (by - cz)/((b + c)(y - z)) + (cz - az)/((c + a)(z - x)) = 3`
If a + b : a - b = 11 : 8 ; find the vaIue of a : b
Express the following ratios in its simplest form :
200:250
Express the following ratios in its simplest form :
x2 : 4x
In a business, A invests Rs 50000 for 6 months, B Rs 60000 for 4 months and C, Rs 80000 for 5 months. If they together earn Rs 18800 find the share of each.
If `x/a = y/b = z/c`, prove that `(3x^3 - 5y^3 + 4z^3)/(3a^3 - 5b^3 + 4c^3) = ((3x - 5y + 4z)/(3a - 5b + 4c))^3`.
When Chinmay visted chowpati at Mumbai on a holiday, he observed that the ratio of North Indian food stalls to South Indian food stalls is 5 : 4. If the total number of food stalls is 117, find the number of each type of food stalls.
Find the ratio of the following:
98 to 63
Given below is a Mathematical term.
Find the ratio of consonants to vowels in the term.
