Question

Ranbeer runs 10 km due North and 24 km due West. The distance between his two positions is ______.

Options

• 34 km

• 17 km

• 26 km

• none of these

Answer 1

Ranbeer runs 10 km due North and 24 km due West. The distance between his two positions is 26 km.

Explanation:

By applying Pythagoras’ theorem to the right-angled triangle formed by the northward and westward paths, the distance between the two positions is,

`sqrt{10^2 + 24^2} = sqrt{100 + 576} = sqrt{676} = 26" km"`.