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प्रश्न
Ranbeer runs 10 km due North and 24 km due West. The distance between his two positions is ______.
पर्याय
34 km
17 km
26 km
none of these
MCQ
रिकाम्या जागा भरा
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उत्तर
Ranbeer runs 10 km due North and 24 km due West. The distance between his two positions is 26 km.
Explanation:
By applying Pythagoras’ theorem to the right-angled triangle formed by the northward and westward paths, the distance between the two positions is,
`sqrt{10^2 + 24^2} = sqrt{100 + 576} = sqrt{676} = 26" km"`.
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