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Maharashtra State BoardSSC (English Medium) 10th Standard

Prove that: tan AtanACot ACotAsin A cos Atan A(1+tan2A)2+Cot A(1+Cot2A)2=sin A cos A.

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Question

Prove that:

`"tan A"/(1 + "tan"^2 "A")^2 + "Cot A"/(1 + "Cot"^2 "A")^2 = "sin A cos A"`.

Sum
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Solution

`"tan A"/(1 + "tan"^2 "A")^2 + "cot A"/(1 + "cot"^2 "A")^2 = "sin A cos A"`.

LHS = `"tan A"/(1 + "tan"^2 "A")^2 + "cot A"/(1 + "cot"^2 "A")^2`

LHS =  `"tan A"/("sec"^2 "A")^2 + "cot A"/("cosec"^2 "A")^2         ...{( 1 + "tan"^2θ = "sec"^2θ),(1 + "cot"^2θ = "cosec"^2θ):}`

LHS = `"tan A" × 1/("sec"^2 "A")^2 + "cot A" × 1/("cosec"^2 "A")^2`

LHS = `"sin A"/"cos A" × "cos"^4 "A" + "cos A"/"sin A" × "sin"^4 "A"   ...{(cosθ = 1/sec θ),(sin θ = 1/"cosecθ"):}`

LHS = sinA cos3A + cosA sin3A

LHS = sinA cosA (cos2A  + sin2A)

LHS = sinA cosA.(1)                ...(cos2A  + sin2A = 1)

LHS = sinA cosA

RHS = sinA cosA

LHS = RHS

Hence proved.

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Chapter 6: Trigonometry - Practice Set 6.1 [Page 131]

APPEARS IN

Balbharati Geometry Mathematics 2 [English] Standard 10 Maharashtra State Board
Chapter 6 Trigonometry
Practice Set 6.1 | Q 6.10 | Page 131

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