Advertisements
Advertisements
Question
Prove that:
(tan A + cot A) (cosec A – sin A) (sec A – cos A) = 1
Advertisements
Solution
(tan A + cot A) (cosec A – sin A) (sec A – cos A)
= `(sinA/cosA + cosA/sinA)(1/sinA - sinA)(1/cosA - cosA)`
= `((sin^2A + cos^2A)/(sinAcosA))((1 - sin^2A)/sinA)((1 - cos^2A)/cosA)`
= `(1/(sinAcosA))(cos^2A/sinA)(sin^2A/cosA)`
= 1
APPEARS IN
RELATED QUESTIONS
Show that : `sinA/sin(90^circ - A) + cosA/cos(90^circ - A) = sec A cosec A`

From the figure find the value of sinθ.
If sec2 θ (1 + sin θ) (1 − sin θ) = k, then find the value of k.
\[\frac{x^2 - 1}{2x}\] is equal to
The value of sin2 29° + sin2 61° is
Prove the following identity :
`sinθ(1 + tanθ) + cosθ(1 +cotθ) = secθ + cosecθ`
Prove that cosec2 (90° - θ) + cot2 (90° - θ) = 1 + 2 tan2 θ.
If x sin3θ + y cos3 θ = sin θ cos θ and x sin θ = y cos θ , then show that x2 + y2 = 1.
Prove that cos θ sin (90° - θ) + sin θ cos (90° - θ) = 1.
Prove that `(1 + sec A)/(sec A) = (sin^2A)/(1 - cos A)`.
