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Question
Prove that:
(sin A + cos A) (sec A + cosec A) = 2 + sec A cosec A
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Solution
(sin A + cos A) (sec A + cosec A)
= `sinA/cosA + 1 + 1 + cosA/sinA`
= `2 + (cos^2A + sin^2A)/(sinAcosA)`
= `2 + 1/(sinAcosA)`
= 2 + sec A cosec A
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