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Prove that following number is irrational: [\frac{3}{2\sqrt{5}}\

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Question

Prove that following number is irrational:

\[\frac{3}{2\sqrt{5}}\]
Theorem
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Solution

Let us assume that 

\[\frac{3}{2\sqrt{5}}\] is rational. Then, there exist positive co primes a and b such that
\[\frac{3}{2\sqrt{5}}\] `=a/b`
`sqrt5=(3b)/(2a)`
Hence \[\frac{3}{2\sqrt{5}}\] is irrational
`sqrt5` is a rational numbers which is a contradication.
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Chapter 1: Real Numbers - EXERCISE 1.5 [Page 1.36]

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R.D. Sharma Mathematics [English] Class 10
Chapter 1 Real Numbers
EXERCISE 1.5 | Q 2. (ii) | Page 1.36
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