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Question
Prove that following number is irrational:
\[\frac{3}{2\sqrt{5}}\]
Theorem
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Solution
Let us assume that
\[\frac{3}{2\sqrt{5}}\] is rational. Then, there exist positive co primes a and b such that
\[\frac{3}{2\sqrt{5}}\] `=a/b`
`sqrt5=(3b)/(2a)`
Hence \[\frac{3}{2\sqrt{5}}\] is irrational
`sqrt5` is a rational numbers which is a contradication.
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Chapter 1: Real Numbers - EXERCISE 1.5 [Page 1.36]
