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प्रश्न
Prove that following number is irrational:
\[\frac{3}{2\sqrt{5}}\]
सिद्धांत
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उत्तर
Let us assume that
\[\frac{3}{2\sqrt{5}}\] is rational. Then, there exist positive co primes a and b such that
\[\frac{3}{2\sqrt{5}}\] `=a/b`
`sqrt5=(3b)/(2a)`
Hence \[\frac{3}{2\sqrt{5}}\] is irrational
`sqrt5` is a rational numbers which is a contradication.
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या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 1: Real Numbers - EXERCISE 1.5 [पृष्ठ १.३६]
