Advertisements
Advertisements
Question
Prove that
Advertisements
Solution
LHS = \[\frac{cosec \left( 90^\circ + x \right) + \cot \left( 450^\circ + x \right)}{cosec \left( 90^\circ - x \right) + \tan \left( 180^\circ - x \right)} + \frac{\tan \left( 180^\circ + x \right) + \sec \left( 180^\circ - x \right)}{\tan \left( 360^\circ + x \right) - \sec \left( - x \right)}\]
\[ = \frac{cosec\left( 90^\circ + x \right) + \cot\left( 450^\circ + x \right)}{cosec \left( 90^\circ - x \right) + \tan\left( 180^\circ - x \right)} + \frac{\tan \left( 180^\circ + x \right) + \sec \left( 180^\circ - x \right)}{\tan \left( 360^\circ + x \right) - \sec \left( - x \right)}\]
\[ = \frac{cosec\left( 90^\circ + x \right) + \cot \left( 90^\circ \times 5 + x \right)}{cosec\left( 90^\circ - x \right) + \tan \left( 90^\circ \times 2 - x \right)} + \frac{\tan \left( 90^\circ \times 2 + x \right) + \sec \left( 90^\circ \times 2 - x \right)}{\tan\left( 90^\circ \times 4 + x \right) - \sec\left( - x \right)}\]
\[ = \frac{\sec x + \cot \left( 90^\circ \times 5 + x \right)}{cosec\left( 90^\circ- x \right) + \tan \left( 90^\circ \times 2 - x \right)} + \frac{\tan \left( 90^\circ \times 2 + x \right) + \sec \left( 90^\circ \times 2 - x \right)}{\tan \left( 90^\circ \times 4 + x \right) - \sec \left( - x \right)}\]
\[ = \frac{\sec x - \tan x}{\sec x - \tan x} + \frac{\tan x - \sec x}{\tan x - \sec x}\]
\[ = 1 + 1\]
\[ = 2\]
= RHS
Hence proved.
APPEARS IN
RELATED QUESTIONS
If \[\sin x + \cos x = m\], then prove that \[\sin^6 x + \cos^6 x = \frac{4 - 3 \left( m^2 - 1 \right)^2}{4}\], where \[m^2 \leq 2\]
If \[a = \sec x - \tan x \text{ and }b = cosec x + \cot x\], then shown that \[ab + a - b + 1 = 0\]
Prove that: tan 225° cot 405° + tan 765° cot 675° = 0
Prove that:
Prove that
Prove that:
\[\sec\left( \frac{3\pi}{2} - x \right)\sec\left( x - \frac{5\pi}{2} \right) + \tan\left( \frac{5\pi}{2} + x \right)\tan\left( x - \frac{3\pi}{2} \right) = - 1 .\]
Prove that:
\[\tan 4\pi - \cos\frac{3\pi}{2} - \sin\frac{5\pi}{6}\cos\frac{2\pi}{3} = \frac{1}{4}\]
Prove that:
If tan x = \[x - \frac{1}{4x}\], then sec x − tan x is equal to
The value of sin25° + sin210° + sin215° + ... + sin285° + sin290° is
If A lies in second quadrant 3tan A + 4 = 0, then the value of 2cot A − 5cosA + sin A is equal to
Which of the following is correct?
Find the general solution of the following equation:
Find the general solution of the following equation:
Find the general solution of the following equation:
Solve the following equation:
Solve the following equation:
Solve the following equation:
Solve the following equation:
Solve the following equation:
\[\sqrt{3} \cos x + \sin x = 1\]
Solve the following equation:
\[\cot x + \tan x = 2\]
Solve the following equation:
\[2 \sin^2 x = 3\cos x, 0 \leq x \leq 2\pi\]
Solve the following equation:
\[2^{\sin^2 x} + 2^{\cos^2 x} = 2\sqrt{2}\]
Write the number of points of intersection of the curves
Write the number of values of x in [0, 2π] that satisfy the equation \[\sin x - \cos x = \frac{1}{4}\].
If \[3\tan\left( x - 15^\circ \right) = \tan\left( x + 15^\circ \right)\] \[0 < x < 90^\circ\], find θ.
If \[4 \sin^2 x = 1\], then the values of x are
In (0, π), the number of solutions of the equation \[\tan x + \tan 2x + \tan 3x = \tan x \tan 2x \tan 3x\] is
The equation \[3 \cos x + 4 \sin x = 6\] has .... solution.
General solution of \[\tan 5 x = \cot 2 x\] is
Find the principal solution and general solution of the following:
cot θ = `sqrt(3)`
Solve the following equations for which solution lies in the interval 0° ≤ θ < 360°
2 sin2x + 1 = 3 sin x
Solve the following equations:
2 cos2θ + 3 sin θ – 3 = θ
Solve the following equations:
`tan theta + tan (theta + pi/3) + tan (theta + (2pi)/3) = sqrt(3)`
Choose the correct alternative:
If cos pθ + cos qθ = 0 and if p ≠ q, then θ is equal to (n is any integer)
Solve 2 tan2x + sec2x = 2 for 0 ≤ x ≤ 2π.
