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Question
Prove log a + log a2 + log a3 + · · · + log an = `("n"("n" + 1))/2 log "a"`
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Solution
log a + log a2 + log a3 + ……… + log an
= log a + 2 log a + 3 log a + ………….. + n log a
= log a (1 + 2 + 3 + ………….. + n)
= `log "a" xx ("n"("n" + 1))/2`
= `("n"("n" + 1))/2 log "a"`
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