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Question
Prove `log "a"^2/"bc" + log "b"^2/"ca" + log "c"^2/"ab"` = 0
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Solution
`log "a"^2/"bc" + log "b"^2/"ca" + log "c"^2/"ab" = log ("a"^2/"bc") ("b"^2/"ca") ("c"^2/"ab")`
= `log ("a"^2 "b"^2 "c"^2)/("a"^2 "b"^2 "c"^2)`
= log 1
= 0
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