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PQRS is a rectangle inscribed in a quadrant of a circle of radius 13 cm. A is any point on PQ. If PS = 5 cm, then ar (PAS) = 30 cm2.

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Question

PQRS is a rectangle inscribed in a quadrant of a circle of radius 13 cm. A is any point on PQ. If PS = 5 cm, then ar (PAS) = 30 cm2.

Options

  • True

  • False

MCQ
True or False
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Solution

This statement is True.

Explanation:

Given, PS = 5 cm

Radius of circle = SQ = 13 cm

In right-angled ΔSPQ,

SQ2 = PQ2 + PS2   ...[By Pythagoras theorem]

(13)2 = PQ2 + (5)2

⇒ PQ2 = 169 – 25 = 144

⇒ PQ = 12 cm  ...[Taking positive square root, because length is always positive]

Now, area of ΔAPS = `1/2` × Base × Height

= `1/2 xx PS xx PQ`

= `1/2 xx 5 xx 12`

= 30 cm2 

So, given statement is true, if A coincides Q.

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Chapter 9: Areas of Parallelograms & Triangles - Exercise 9.2 [Page 88]

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NCERT Exemplar Mathematics Exemplar [English] Class 9
Chapter 9 Areas of Parallelograms & Triangles
Exercise 9.2 | Q 2. | Page 88

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