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Question
PQRS is a parallelogram. PQ is produced to T so that PQ = QT. Prove that PQ = QT. Prove that ST bisects QR.
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Solution
PQ = QT
But PQ = SR ...(PQRS is a parallelogram)
Therefore, QT = SR
In ΔSOR and ΔQAT
QT = SR
∠3 = ∠4 ...(vertically opposite angles)
∠1 = ∠2 ...(alternate angles since PQ || SR)
Therefore, ΔSOR ≅ ΔQAT
Hence, OS = OT and OR = OQ
Therefore, ST bisects QR.
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