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P If a is Any Set, Prove That: a ⊆ ϕ ⇔ a = ϕ .

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Question

If A is any set, prove that: \[A \subseteq \phi \Leftrightarrow A = \phi .\] 

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Solution

To prove: \[A \subseteq \phi \Leftrightarrow A = \phi\]

Proof:
Let: \[A \subseteq \phi\] 

If A is a subset of an empty set, then A is the empty set.
∴\[A \subseteq \phi\]

Now, let 

\[A = \phi\]

This means that is an empty set.
We know that every set is a subset of itself.

\[A = \phi\]   

Thus, we have \[A \subseteq \phi \Leftrightarrow A = \phi\]

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Chapter 1: Sets - Exercise 1.04 [Page 17]

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RD Sharma Mathematics [English] Class 11
Chapter 1 Sets
Exercise 1.04 | Q 12 | Page 17

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