Advertisements
Advertisements
Question
On what date will ₹ 1950 lent on 5th January 2011 amount to ₹ 2125.50 at 5 percent per annum simple interest?
Advertisements
Solution
P = Rs.1950
A = Rs.2125.50
R = 5% P.a.
I = A − P
= Rs.2125.50 − Rs,1950
= Rs.175.50
T =`(100xx"I")/("P"xx"R")`
`=(100xx175.50)/(1950xx5)`
`=17550/9750=1755/975=117/65`
`=9/5` years =`1 4/5` years
= 1 years 292 days
∵ `4/5` years
`=4/5xx365` days = 292 days
Jan. + Feb. + March + April + May + June + July +Aug. + Sept. + Oct.
(31 − 5) + 29 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 23
= 292 days
∴ Required date = 23rd October 2012
APPEARS IN
RELATED QUESTIONS
Find the interest and the amount on:
₹ 5,000 at 8% per year from 23rd December 2011 to 29th July 2012.
What sum of money borrowed on 24th May will amount to Rs.10210.20 on 17th October of the same year at 5 percent per annum simple interest.
The interest on a certain sum of money is 0.24 times itself in 3 years. Find the rate of interest.
Angela deposited 15000 rupees in a bank at a rate of 9 p.c.p.a. She got simple interest amounting to 5400 rupees. For how many years had she deposited the amount?
In what time will ₹ 17800 amount to ₹ 19936 at 6% per annum?
The interest for a principle of ₹ 4,500 which gives an amount of ₹ 5,000 at end of certain period is
Which among the following is the simple interest for the principle of ₹ 1,000 for one year at the rate of 10% interest per annum?
The value of a machine depreciates at 10% per year. If the present value is ₹ 1,62,000, what is the worth of the machine after two years?
The difference of interest for 2 years and 3 years on a sum of ₹ 2100 at 8% per annum is ______.
Bhavya earns ₹ 50,000 per month and spends 80% of it. Due to pay revision, her monthly income increases by 20% but due to price rise, she has to spend 20% more. Find her new savings.
