Advertisements
Advertisements
Question
On what date will ₹ 1950 lent on 5th January 2011 amount to ₹ 2125.50 at 5 percent per annum simple interest?
Advertisements
Solution
P = Rs.1950
A = Rs.2125.50
R = 5% P.a.
I = A − P
= Rs.2125.50 − Rs,1950
= Rs.175.50
T =`(100xx"I")/("P"xx"R")`
`=(100xx175.50)/(1950xx5)`
`=17550/9750=1755/975=117/65`
`=9/5` years =`1 4/5` years
= 1 years 292 days
∵ `4/5` years
`=4/5xx365` days = 292 days
Jan. + Feb. + March + April + May + June + July +Aug. + Sept. + Oct.
(31 − 5) + 29 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 23
= 292 days
∴ Required date = 23rd October 2012
APPEARS IN
RELATED QUESTIONS
What sum of money borrowed on 24th May will amount to Rs.10210.20 on 17th October of the same year at 5 percent per annum simple interest.
The interest on a certain sum of money is 0.24 times itself in 3 years. Find the rate of interest.
Stephen invested ₹ 10,000 in a savings bank account that earned 2% simple interest. Find the interest earned if the amount was kept in the bank for 4 years
If a principal is getting doubled after 4 years, then calculate the rate of interest. (Hint: Let P = ₹ 100)
The time period after which the interest is added each time to form a new principal is called the ______.
Given the principal = Rs 40,000, rate of interest = 8% p.a. compounded annually. Find principal for 2nd year.
Gayatri’s income is ₹ 1,60,000 per year. She pays 15% of this as house rent and 10% of the remainder on her child’s education. The money left with her is ______.
Amount received on ₹ 3000 for 2 years at the rate of 11% per annum is ______.
Interest on ₹ 12000 for 1 month at the rate of 10% per annum is ______.
Chalk contains 10% calcium, 3% carbon and 12% oxygen. Find the amount of carbon and calcium (in grams) in `2 1/2` kg of chalk.
