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On dividing p(4p2 – 16) by 4p(p – 2), we get ______. - Mathematics

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Question

On dividing p(4p2 – 16) by 4p(p – 2), we get ______.

Options

  • 2p + 4

  • 2p – 4

  • p + 2

  • p – 2

MCQ
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Solution

On dividing p(4p2 – 16) by 4p(p – 2), we get p + 2.

Explanation:

We have,

`(p(4p^2 - 16))/(4p(p - 2)) = (p[(2p)^2 - 4^2])/(4p(p - 2))`

= `((2p - 4)(2p + 4))/(4(p - 2))`  ...[∵ a2 – b2 = (a + b)(a – b)]

= `(2(p - 2)*2(p + 2))/(4(p - 2))`

= `(4(p - 2)(p + 2))/(4(p - 2))`

= p + 2

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Chapter 7: Algebraic Expression, Identities and Factorisation - Exercise [Page 227]

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NCERT Exemplar Mathematics [English] Class 8
Chapter 7 Algebraic Expression, Identities and Factorisation
Exercise | Q 23. | Page 227

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