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On a map drawn to a scale of 1 : 25000, a rectangular plot of land, ABCD, is measured as AB = 12 cm and BC = 16 cm. Calculate the diagonal distance of the plot in km and the plot area in km2. - Mathematics

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Questions

On a map drawn to a scale of 1 : 25000, a rectangular plot of land, ABCD, is measured as AB = 12 cm and BC = 16 cm. Calculate the diagonal distance of the plot in km and the plot area in km2

On a map drawn to a scale of 1 : 25000, a rectangular plot of land, ABCD, has the following measurements: AB = 12 cm and BC = 16 cm. Angles A, B, C and D are 90° each. Calculate:

  1. The distance of a diagonal of the plot in km.
  2. The area of the plot in sq. km.
Sum
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Solution

Scale:- 1 : 25000

1 cm represents 25000 cm = `25000/(1000 xx 100) = 0.25` km

1 cm represents 0.25 km

(i)

AC2 = AB2 + BC2

= 122 + 162

= 144 + 256

AC = 400

AC = 20 cm

Actual length of diagonal = 20 × 0.25

= 5.00

= 5 km

Hence, the distance of a diagonal of the plot in km is 5 km.

(ii)

1 cm represents 0.25 km,

1 cm2 represents 0.25 × 0.25 km2

The area of the rectangle ABCD =  AB × BC

= 16 × 12

= 192 cm2

The area of the plot = 0.25 × 0.25 × 192 km2

Hence, the area of the plot in sq. km = 12 km2

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Chapter 15: Similarity - Exercise 15.2

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Frank Mathematics - Part 2 [English] Class 10 ICSE
Chapter 15 Similarity
Exercise 15.2 | Q 9
Nootan Mathematics [English] Class 10 ICSE
Chapter 13 Similarity
Exercise 13C | Q 3. | Page 289
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