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प्रश्न
On a map drawn to a scale of 1 : 25000, a rectangular plot of land, ABCD, is measured as AB = 12 cm and BC = 16 cm. Calculate the diagonal distance of the plot in km and the plot area in km2.
On a map drawn to a scale of 1 : 25000, a rectangular plot of land, ABCD, has the following measurements: AB = 12 cm and BC = 16 cm. Angles A, B, C and D are 90° each. Calculate:
- The distance of a diagonal of the plot in km.
- The area of the plot in sq. km.
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उत्तर
Scale:- 1 : 25000
1 cm represents 25000 cm = `25000/(1000 xx 100) = 0.25` km
1 cm represents 0.25 km

(i)
AC2 = AB2 + BC2
= 122 + 162
= 144 + 256
AC2 = 400
AC = 20 cm
Actual length of diagonal = 20 × 0.25
= 5.00
= 5 km
Hence, the distance of a diagonal of the plot in km is 5 km.
(ii)
1 cm represents 0.25 km,
1 cm2 represents 0.25 × 0.25 km2
The area of the rectangle ABCD = AB × BC
= 16 × 12
= 192 cm2
The area of the plot = 0.25 × 0.25 × 192 km2
Hence, the area of the plot in sq. km = 12 km2
