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Question
Offices in Delhi are open for five days in a week (Monday to Friday). Two employees of an office remain absent for one day in the same particular week. Find the probability that they remain absent on different days.
Sum
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Solution
Total number of possible outcomes = 5 × 5 = 25
The possible outcomes are:
MM, MT, MW, MTh, MF, TM, TT, TW, TTh, TF, WM, WT, WW, WTh, WF, ThM, ThT, ThW, ThTh, ThF, FM, FT, FW, FTh, FF
P(absent on different days) = 1 – P(absent on same days)
= `1 - 1/5`
= `4/5`
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