Question

Offices in Delhi are open for five days in a week (Monday to Friday). Two employees of an office remain absent for one day in the same particular week. Find the probability that they remain absent on different days. 

Answer 1

Total number of possible outcomes = 5 × 5 = 25 

The possible outcomes are: 

MM, MT, MW, MTh, MF, TM, TT, TW, TTh, TF, WM, WT, WW, WTh, WF, ThM, ThT, ThW, ThTh, ThF, FM, FT, FW, FTh, FF 

P(absent on different days) = 1 – P(absent on same days)  

= `1 - 1/5` 

= `4/5`