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Question
Obtain an expression for electric potential (V) at a point near a point charge ‘Q’.
Derivation
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Solution

F = `1/(4 pi epsilon_0) * (Q xx 1)/x^2`
= `(1/(4 pi epsilon_0)) Q/x^2`
dW = −Fdx
= `-(1/(4 pi epsilon_0)) Q/x^2 dx`
Since the test charge is +1, V = W. Therefore,
V = `int_infty^r dW`
= `int_infty^r - (1/(4 pi epsilon_0)) Q/x^2 dx`
= `-Q/(4 pi epsilon_0) int_infty^r x^-2 dx`
= `-Q/(4 pi epsilon_0) [-1/x]_infty^r`
= `Q/(4 pi epsilon_0) (1/r - 0)`
= `(1/(4 pi epsilon_0)) Q/r`
This is the desired expression.
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