Advertisements
Advertisements
प्रश्न
Obtain an expression for electric potential (V) at a point near a point charge ‘Q’.
व्युत्पत्ति
Advertisements
उत्तर

F = `1/(4 pi epsilon_0) * (Q xx 1)/x^2`
= `(1/(4 pi epsilon_0)) Q/x^2`
dW = −Fdx
= `-(1/(4 pi epsilon_0)) Q/x^2 dx`
Since the test charge is +1, V = W. Therefore,
V = `int_infty^r dW`
= `int_infty^r - (1/(4 pi epsilon_0)) Q/x^2 dx`
= `-Q/(4 pi epsilon_0) int_infty^r x^-2 dx`
= `-Q/(4 pi epsilon_0) [-1/x]_infty^r`
= `Q/(4 pi epsilon_0) (1/r - 0)`
= `(1/(4 pi epsilon_0)) Q/r`
This is the desired expression.
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
