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In the photoelectric effect, the maximum kinetic energy of the emitted photoelectron is ‘a’ and the work function of the metal is W0. If the frequency of incident radiation is made ‘K’ times, then - Physics (Theory)

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Question

In the photoelectric effect, the maximum kinetic energy of the emitted photoelectron is ‘a’ and the work function of the metal is W0. If the frequency of incident radiation is made ‘K’ times, then calculate the change in maximum KE of the ejected electron.

Derivation
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Solution

Given a = hv – W0

⇒ hv = a + W0

New frequency = Kν

`K_"max"^'` = h(Kν) – W0

= Khv – W0

Change in maximum kinetic energy:

`ΔK_"max" = K_"max"^' - a`

= (khv – W0) – (hv – W0)

= (K – 1)hv 

Now substitute hν = a + W0​:

ΔKmax = (K – 1) (a + W0​)

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