Advertisements
Advertisements
Question
Number of circles that can be drawn through three non-collinear points is
Options
1
0
2
3
Advertisements
Solution
Suppose we are given three non-collinear points as A, B and C

1. Join A and B.
2. Join B and C.
3. Draw perpendicular bisector of AB and BC which meet at O as centre of the circle.
So basically we can only draw one circle passing through three non-collinear points A, B and C.
APPEARS IN
RELATED QUESTIONS
In the given figure, O is the centre of the circle. PA and PB are tangents. Show that AOBP is a cyclic quadrilateral.

In two concentric circles, a chord of length 8 cm of the large circle touches the smaller circle. If the radius of the larger circle is 5 cm, then find the radius of the smaller circle.
The radius of a circle is 6 cm. The perpendicular distance from the centre of the circle to the chord which is 8 cm in length, is
State, if the following statement is true or false:
The longest chord of a circle is its diameter.
The length of the tangent from point A to a circle, of radius 3 cm, is 4 cm. The distance of A from the centre of the circle is ______
In the following figure, if OA = 5 cm, AB = 8 cm and OD is perpendicular to AB, then CD is equal to ______.

In the following figure, if AOB is a diameter of the circle and AC = BC, then ∠CAB is equal to ______.

AB and AC are two equal chords of a circle. Prove that the bisector of the angle BAC passes through the centre of the circle.
In the following figure, O is the centre of the circle, BD = OD and CD ⊥ AB. Find ∠CAB.

Draw any circle and mark
- it's centre
- a radius
- a diameter
- a sector
- a segment
- a point in its interior
- a point in its exterior
- an arc
