Advertisements
Advertisements
प्रश्न
Number of circles that can be drawn through three non-collinear points is
विकल्प
1
0
2
3
Advertisements
उत्तर
Suppose we are given three non-collinear points as A, B and C

1. Join A and B.
2. Join B and C.
3. Draw perpendicular bisector of AB and BC which meet at O as centre of the circle.
So basically we can only draw one circle passing through three non-collinear points A, B and C.
APPEARS IN
संबंधित प्रश्न
Fill in the blank
Circles having the same centre and different radii are called ...........................circles.
In the given figure, an isosceles triangle ABC, with AB = AC, circumscribes a circle. Prove that point of contact P bisects the base BC.

In the given figure common tangents AB and CD to the two circles with centres O1 and O2 intersect at E. Prove that AB=CD

In the given figure, a triangle ABC is drawn to circumscribe a circle of radius 2 cm such that the segments BD and DC into which BC is divided by the point of contact D, are of lengths 4cm and 3cm respectively. If the area of 2 ABC 21cm then find the lengths of sides AB and AC.

In the given figure, PA and PB are two tangents to the circle with centre O. If ∠APB = 60° then find the measure of ∠OAB.

In the given figure, ABCD is a cyclic quadrilateral. If ∠BCD = 100° and ∠ABD = 70°, find ∠ADB.

In the given figure, two tangents AB and AC are drawn to a circle with centre O such that ∠BAC = 120°. Prove that OA = 2AB.

Construct a triangle ABC with AB = 5 cm, ∠B = 60° and BC = 6. 4 cm. Draw the incircle of the triangle ABC.
In the figure, O is the centre of a circle, AB is a chord, and AT is the tangent at A. If ∠AOB = 100°, then ∠BAT is equal to ______
In the adjoining figure, AC is a diameter of the circle. AP = 3 cm and PB = 4 cm and QP ⊥ AB. If the area of ΔAPQ is 18 cm2, then the area of shaded portion QPBC is ______.

