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Maharashtra State BoardSSC (English Medium) 10th Standard

Name Ethene Propene 1-Butene 1-Pentene Molecular formula C2H4 C3H6 C4H8 C5H10 Condensed Structural formula CH2 = CH2 CH3 - CH = CH2 CH3 - CH2 - CH = CH2 CH3 - CH2 - CH2 - CH = CH2

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Question

Name Molecular formula Condensed Structural formula Number of carbon atoms Number of -CH2 - units Boiling point °C
Ethene C2H4 \[\ce{CH2 = CH2}\] 2 0 −102
Propene C3H6 \[\ce{CH3 - CH = CH2}\] 3 1 −48
1-Butene C4H8 \[\ce{CH3 - CH2 - CH = CH2}\] 4 2 −6.5
1-Pentene C5H10 \[\ce{CH3 - CH2 - CH2 - CH = CH2}\] 5 3 30

The above table shows the homologous series of alkenes. Inspect the molecular formulae of the members of this series. Do you find any relationship, in the number of carbon atoms and the number of hydrogen atoms in the molecular formulae?

Very Short Answer
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Solution

If we look at the molecular formulas of alkenes in the mentioned homologous series, we can see that there are half as many carbon atoms as hydrogen atoms.

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Chapter 9: Carbon Compounds - Intext Questions [Page 120]

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Balbharati Science and Technology Part 1 [English] Standard 10 Maharashtra State Board
Chapter 9 Carbon Compounds
Intext Questions | Q 1. | Page 120
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