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Question
My younger sister's age today is 3 times, what it will be 3 years from now minus 3 times what her age was 3 years ago. Find her present age.
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Solution
Let the age of my younger sister be x yr.
Then, her age after 3 yr = (x + 3) yr
Also, her age 3 yr ago = (x – 3) yr
It is given that her present age is 3 times her age after 3 yr minus 3 times her age 3 yr ago
Therefore, we obtain the following equation
x = 3(x + 3) – 3(x – 3)
⇒ 3x + 9 – 3x + 9 ...[Using the distribute property]
⇒ x = 18 yr
Hence, her present age is 18 yr.
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