Advertisements
Advertisements
Question
Multiply the following:
`(3/4x - 4/3 y), (2/3x + 3/2y)`
Advertisements
Solution
We have,
`(3/4x - 4/3 y)` and `(2/3x + 3/2y)`
∴ `(3/4 x - 4/3y)(2/3x + 3/2y) = 3/4x (2/3x + 3/2y) - 4/3y (2/3x + 3/2y)`
= `3/4 xx 2/3 x^2 + 3/4 xx 3/2 xy - 4/3 xx 2/3 yx - 4/3 xx 3/2 y^2`
= `1/2 x^2 + 9/8 xy - 8/9 xy - 2y^2`
= `1/2 x^2 + (9/8 - 8/9)xy - 2y^2`
= `1/2 x^2 + ((81 - 64)/72)xy - 2y^2`
= `1/2 x^2 + 17/72 xy - 2y^2`
APPEARS IN
RELATED QUESTIONS
Simplify.
(x2 − 5) (x + 5) + 25
Simplify.
(a2 + 5) (b3 + 3) + 5
Simplify.
(x + y) (2x + y) + (x + 2y) (x − y)
Simplify.
(a + b + c) (a + b − c)
Write the following square of binomial as trinomial: (x + 2)2
Write the following square of binomial as trinomial: \[\left( 9a + \frac{1}{6} \right)^2\]
Write the following square of binomial as trinomial: \[\left( \frac{x}{4} - \frac{y}{3} \right)\]
Write the following square of binomial as trinomial: \[\left( 3x - \frac{1}{3x} \right)^2\]
Write the following square of binomial as trinomial: (x2 − ay)2
Multiply the following:
–7st, –1, –13st2
