Advertisements
Advertisements
प्रश्न
Multiply the following:
`(3/4x - 4/3 y), (2/3x + 3/2y)`
Advertisements
उत्तर
We have,
`(3/4x - 4/3 y)` and `(2/3x + 3/2y)`
∴ `(3/4 x - 4/3y)(2/3x + 3/2y) = 3/4x (2/3x + 3/2y) - 4/3y (2/3x + 3/2y)`
= `3/4 xx 2/3 x^2 + 3/4 xx 3/2 xy - 4/3 xx 2/3 yx - 4/3 xx 3/2 y^2`
= `1/2 x^2 + 9/8 xy - 8/9 xy - 2y^2`
= `1/2 x^2 + (9/8 - 8/9)xy - 2y^2`
= `1/2 x^2 + ((81 - 64)/72)xy - 2y^2`
= `1/2 x^2 + 17/72 xy - 2y^2`
APPEARS IN
संबंधित प्रश्न
Simplify.
(x2 − 5) (x + 5) + 25
Simplify.
(x + y) (2x + y) + (x + 2y) (x − y)
Simplify.
(1.5x − 4y) (1.5x + 4y + 3) − 4.5x + 12y
Simplify.
(a + b + c) (a + b − c)
Write the following square of binomial as trinomial: (8a + 3b)2
Write the following square of binomial as trinomial:
\[\left( x + \frac{x^2}{2} \right)^2\]
Write the following square of binomial as trinomial: \[\left( \frac{x}{4} - \frac{y}{3} \right)\]
Write the following square of binomial as trinomial: (x2 − ay)2
p2q + q2r + r2q is a binomial.
Multiply the following:
`3/2 p^2 + 2/3 q^2, (2p^2 - 3q^2)`
