Advertisements
Advertisements
प्रश्न
Product of 6a2 – 7b + 5ab and 2ab is ______.
विकल्प
12a3b – 14ab2 + 10ab
12a3b – 14ab2 + 10a2b2
6a2 – 7b + 7ab
12a2b – 7ab2 + 10ab
Advertisements
उत्तर
Product of 6a2 – 7b + 5ab and 2ab is 12a3b – 14ab2 + 10a2b2.
Explanation:
Required product = 2ab × (6a2 – 7b + 5ab)
This is the product of a trinomial by a monomial, so we multiply monomial with each term of the trinomial.
∴ 2ab × (6a2 – 7b + 5ab) = 2ab × 6a2 + 2ab(–7b) + 2ab × 5ab
= 12a3b – 14ab2 + 10a2b2
APPEARS IN
संबंधित प्रश्न
Simplify.
(a2 + 5) (b3 + 3) + 5
Simplify.
(a + b) (c − d) + (a − b) (c + d) + 2 (ac + bd)
Simplify.
(x + y) (x2 − xy + y2)
Simplify.
(1.5x − 4y) (1.5x + 4y + 3) − 4.5x + 12y
Write the following square of binomial as trinomial: \[\left( 9a + \frac{1}{6} \right)^2\]
Write the following square of binomial as trinomial:
\[\left( x + \frac{x^2}{2} \right)^2\]
Write the following square of binomial as trinomial: \[\left( 3x - \frac{1}{3x} \right)^2\]
Write the following square of binomial as trinomial: \[\left( \frac{x}{y} - \frac{y}{x} \right)^2\]
p2q + q2r + r2q is a binomial.
Multiply the following:
`3/2 p^2 + 2/3 q^2, (2p^2 - 3q^2)`
