Question

\[\ce{MnO2 + 4HCl -> MnCl2 + 2H2O + Cl2}\]

0.02 moles of pure MnO₂ is heated strongly with conc. HCl. Calculate the volume of chlorine gas formed at S.T.P.

Answer 1

1 mole of chlorine gas has volume = 22.4 dm³

So, 0.02 mole will have volume = 22.4 × 0.02

= 0.448 dm³