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Karnataka Board PUCPUC Science Class 11

Li+ Time Period of the Revolution of the Particle, T = 2 π M Q B as Frequency is the Reciprocal of Time Period, So F = Q B 2 π M the Charge on All the Four Particles is Same. but the Mass is - Physics

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Question

Which of the following particles will have minimum frequency of revolution when projected with the same velocity perpendicular to a magnetic field?

Options

  •  Electron

  • Proton

  • He+

  • Li+

MCQ
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Solution

Li+

Time period of the revolution of the particle, `T = (2pim)/(qB)`
As frequency is the reciprocal of time period, so  `f =(qB)/(2pim)`
The charge on all the four particles is same. But the mass is maximum for Li+. So, it will have the smallest frequency of revolution.

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Chapter 12: Magnetic Field - MCQ [Page 229]

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HC Verma Concepts of Physics Vol. 2 [English] Class 11 and 12
Chapter 12 Magnetic Field
MCQ | Q 5 | Page 229

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