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Li+ Time Period of the Revolution of the Particle, T = 2 π M Q B as Frequency is the Reciprocal of Time Period, So F = Q B 2 π M the Charge on All the Four Particles is Same. but the Mass is

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प्रश्न

Which of the following particles will have minimum frequency of revolution when projected with the same velocity perpendicular to a magnetic field?

पर्याय

  •  Electron

  • Proton

  • He+

  • Li+

MCQ
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उत्तर

Li+

Time period of the revolution of the particle, `T = (2pim)/(qB)`
As frequency is the reciprocal of time period, so  `f =(qB)/(2pim)`
The charge on all the four particles is same. But the mass is maximum for Li+. So, it will have the smallest frequency of revolution.

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पाठ 34: Magnetic Field - MCQ [पृष्ठ २२९]

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एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
पाठ 34 Magnetic Field
MCQ | Q 5 | पृष्ठ २२९
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