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Question
Let \[X = A \overline{ BC} + B\overline{ CA} + C\overline{AB } .\] Evaluate X for A = B = C = 1.
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Solution
Given:
Output
\[X = A \overline{ BC} + B\overline{ CA} + C\overline{AB } .\]
A = B = C = 1
\[X = 1 . ( \overline{{1 . 1)}} + 1 . ( \overline{{1 . 1)}} + 1 . ( \overline{{1 . 1)}}\]
\[ = 1 . \bar{1} + 1 . \bar{1} + 1 . \bar{1}\]
\[ = 1 . 0 + 1 . 0 + 1 . 0\]
\[ = 0 + 0 + 0\]
\[ = 0\]
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| 1. | Charge of a proton | (e) | =1.6 × 10-19C |
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