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Let f: R→Rbe defined as f (x) = (x^2 + 1)/2, then ______.

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Question

Let f: R→Rbe defined as f (x) = `(x^2 + 1)/2`, then ______.

Options

  • f is one-one onto

  • fis one-one but not onto

  • fis onto but not one-one

  • fis neither one-one nor onto

MCQ
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Solution

Let f: R→Rbe defined as f (x) = `(x^2 + 1)/2`, then f is neither one-one nor onto.

Explanation:

The function f (x) = `(x^2 + 1)/2` is not one-to-one because it is a symmetric parabola where different inputs can yield the same output; for instance, both x = 1 and x = −1 result in f(x) = 1. It is also not onto because the squared term x2 can never be negative, which restricts the function's range to values ≥ 0.5. Since the function never reaches negative numbers or any value below 0.5, it fails to cover the entire codomain of all real numbers.

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