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Question
Let abc be a three digit number. Then abc + bca + cab is not divisible by ______.
Options
a + b + c
3
37
9
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Solution
Let abc be a three digit number. Then abc + bca + cab is not divisible by 9.
Explanation:
We know that, the sum of three-digit numbers taken in cyclic order can be written as 111(a + b + c).
i.e. abc + bca + cab = 3 × 37 × (a + b + c)
Hence, the sum is divisible by 3, 37 and (a + b + c) but not divisible by 9.
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