Advertisements
Advertisements
प्रश्न
Let abc be a three digit number. Then abc + bca + cab is not divisible by ______.
विकल्प
a + b + c
3
37
9
Advertisements
उत्तर
Let abc be a three digit number. Then abc + bca + cab is not divisible by 9.
Explanation:
We know that, the sum of three-digit numbers taken in cyclic order can be written as 111(a + b + c).
i.e. abc + bca + cab = 3 × 37 × (a + b + c)
Hence, the sum is divisible by 3, 37 and (a + b + c) but not divisible by 9.
APPEARS IN
संबंधित प्रश्न
If 31z5 is a multiple of 9, where z is a digit, what is the value of z? You will find that there are two answers for the last problem. Why is this so?
If 31z5 is a multiple of 3, where z is a digit, what might be the values of z?
Which of the following statement is true?
If a number is divisible by 3, it must be divisible by 9.
Find the quotient when 73 – 37 is divided by 9.
1×5 divisible by 3?
Find the dates of any month in a calendar which are divisible by both 2 and 3.
Let abc be a three-digit number. Then abc – cba is not divisible by ______.
3134673 is divisible by 3 and ______.
Write the smallest digit and the greatest digit in the blank space of the following number so that the number formed is divisible by 3:
______ 6724
What is the rule to check if a number is divisible by 3?
