Advertisements
Advertisements
प्रश्न
If 31z5 is a multiple of 3, where z is a digit, what might be the values of z?
Advertisements
उत्तर
Since 31z5 is a multiple of 3, the sum of its digits will be a multiple of 3.
That is, 3 + 1 + z + 5 = 9 + z is a multiple of 3.
This is possible when 9 + z is any one of 0, 3, 6, 9, 12, 15, 18, and so on …
Since z is a single digit number, the value of 9 + z can only be 9 or 12 or 15 or 18 and thus, the value of x comes to 0 or 3 or 6 or 9 respectively.
Thus, z can have its value as any one of the four different values 0, 3, 6, or 9.
APPEARS IN
संबंधित प्रश्न
If x is a digit of the number \[\overline {{66784x}}\] such that it is divisible by 9, find possible values of x.
Which of the following statement is true?
If a number is divisible by 9, it must be divisible by 3.
Find which of the following numbers are divisible by 3:
(i) 261
(ii) 777
(iii) 6657
(iv) 2574
1×5 divisible by 3?
There are some flowering trees in a garden. Each tree bears many flowers with the same number printed on it. Three children took a basket each to pick flowers. Each basket has one of the numbers, 3, 4 or 9 on it. Each child picks those flowers which have numbers divisible by the number on his or her basket. He/She takes only 1 flower from each tree. Can you tell which numbers the flowers in each basket will have?
If a number is divisible by 6, then it must be divisible by 3
Find the dates of any month in a calendar which are divisible by both 2 and 3.
Why is 872 NOT divisible by 3?
The digit sum of 91 is 10. Therefore, 91 is:
Among 63, 872, and 552, how many numbers are divisible by 3?
