Advertisements
Advertisements
Question
If x is a digit such that the number \[\overline{{18x71}}\] is divisible by 3, find possible values of x.
Advertisements
Solution
\[\text{ It is given that }\overline{{18x71}}\text{ is a multiple of 3}. \]
\[ \therefore (1 + 8 + x + 7 + 1)\text{ is a multiple of 3} . \]
\[ \therefore (17 + x)\text{ is a multiple of 3 }. \]
\[ \therefore 17 + x = 0, 3, 6, 9, 12, 15, 18, 21 . . . \]
\[\text{ But x is a digit . So, x can take values }0, 1, 2, 3, 4 . . . 9 . \]
\[17 + x = 18 \Rightarrow x = 1\]
\[17 + x = 21 \Rightarrow x = 4\]
\[17 + x = 24 \Rightarrow x = 7\]
\[x = 1, 4, 7\]
APPEARS IN
RELATED QUESTIONS
If 21y5 is a multiple of 9, where y is a digit, what is the value of y?
If 31z5 is a multiple of 9, where z is a digit, what is the value of z? You will find that there are two answers for the last problem. Why is this so?
If 31z5 is a multiple of 3, where z is a digit, what might be the values of z?
Given that the number \[\overline{{35\alpha64}}\] is divisible by 3, where α is a digit, what are the possible values of α?
Which of the following statement is true?
If a number is divisible by 9, it must be divisible by 3.
1×5 divisible by 3?
State true or false and explain your answer with reason for the following statement.
A number is divisible by 9, if it is divisible by 3
Find A as required:
The least number 567A is divisible by 3
3134673 is divisible by 3 and ______.
What is the rule to check if a number is divisible by 3?
