English

Integrate the rational function: 2x(x2+1)(x2+3)

Advertisements
Advertisements

Question

Integrate the rational function:

`(2x)/((x^2 + 1)(x^2 + 3))`

Sum
Advertisements

Solution

Let `I = int (2x)/((x^2 + 1)(x^2 + 3))` dx

Putting x2 = t, 2x dx = dt

`therefore I = int dt/((t + 1)(t + 3))`

Now, `1/((t + 1)(t + 3)) = A/(t + 1) = B/(t + 3)`

1 = A(t + 3) + B(t + 1)

Put t = -1

1 = A(-1 + 3)

⇒ 1 = 2A  

∴ A `= 1/2`

Put t = -3

1 = B (-3 + 1)

⇒ 1 = -2B   

∴ B `= -1/2`

`therefore 1/((t + 1)(t + 3)) = 1/(2(t + 1)) - 1/(2(t + 3))`

`therefore I = int 1/((t + 1)(t + 3))  dt = 1/2 int 1/(t + 1)   dt - 1/2 int 1/(t + 3)  dt` 

`= 1/2  log (t + 1) - 1/2  log (t + 3) + C`

`= 1/2  log abs ((t + 1)/(t + 3)) + C`

`= 1/2  log abs ((x^2 + 1)/(x^2 + 3)) + C`

shaalaa.com
  Is there an error in this question or solution?
Chapter 7: Integrals - Exercise 7.5 [Page 323]

APPEARS IN

NCERT Mathematics Part 1 and 2 [English] Class 12
Chapter 7 Integrals
Exercise 7.5 | Q 19 | Page 323

RELATED QUESTIONS

Find: `I=intdx/(sinx+sin2x)`


Integrate the rational function:

`x/((x + 1)(x+ 2))`


Integrate the rational function:

`(2x)/(x^2 + 3x + 2)`


Integrate the rational function:

`(1 - x^2)/(x(1-2x))`


Integrate the rational function:

`2/((1-x)(1+x^2))`


Integrate the rational function:

`(cos x)/((1-sinx)(2 - sin x))` [Hint: Put sin x = t]


Integrate the rational function:

`((x^2 +1)(x^2 + 2))/((x^2 + 3)(x^2+ 4))`


`int (xdx)/((x - 1)(x - 2))` equals:


Find `int(e^x dx)/((e^x - 1)^2 (e^x + 2))`


Integrate the following w.r.t. x : `(1)/(x(x^5 + 1)`


Integrate the following w.r.t. x : `(5x^2 + 20x + 6)/(x^3 + 2x ^2 + x)`


Choose the correct options from the given alternatives :

If `int tan^3x*sec^3x*dx = (1/m)sec^mx - (1/n)sec^n x + c, "then" (m, n)` =


Integrate the following w.r.t. x: `(x^2 + 3)/((x^2 - 1)(x^2 - 2)`


Integrate the following w.r.t.x : `x^2/sqrt(1 - x^6)`


Integrate the following w.r.t.x:

`x^2/((x - 1)(3x - 1)(3x - 2)`


Evaluate:

`int (2x + 1)/(x(x - 1)(x - 4)) dx`.


Evaluate: `int ("x"^2 + "x" - 1)/("x"^2 + "x" - 6)` dx


For `int ("x - 1")/("x + 1")^3  "e"^"x" "dx" = "e"^"x"` f(x) + c, f(x) = (x + 1)2.


`int ((x^2 + 2))/(x^2 + 1) "a"^(x + tan^(-1_x)) "d"x`


`int 1/(2 +  cosx - sinx)  "d"x`


`int "e"^x ((1 + x^2))/(1 + x)^2  "d"x`


`int (6x^3 + 5x^2 - 7)/(3x^2 - 2x - 1)  "d"x`


`int x sin2x cos5x  "d"x`


Evaluate:

`int (5e^x)/((e^x + 1)(e^(2x) + 9)) dx`


Choose the correct alternative:

`int (x + 2)/(2x^2 + 6x + 5) "d"x = "p"int (4x + 6)/(2x^2 + 6x + 5) "d"x + 1/2 int 1/(2x^2 + 6x + 5)"d"x`, then p = ?


If f'(x) = `1/x + x` and f(1) = `5/2`, then f(x) = log x + `x^2/2` + ______ + c


Verify the following using the concept of integration as an antiderivative

`int (x^3"d"x)/(x + 1) = x - x^2/2 + x^3/3 - log|x + 1| + "C"`


Evaluate the following:

`int sqrt(tanx)  "d"x`  (Hint: Put tanx = t2)


Evaluate: `int_-2^1 sqrt(5 - 4x - x^2)dx`


Let g : (0, ∞) `rightarrow` R be a differentiable function such that `int((x(cosx - sinx))/(e^x + 1) + (g(x)(e^x + 1 - xe^x))/(e^x + 1)^2)dx = (xg(x))/(e^x + 1) + c`, for all x > 0, where c is an arbitrary constant. Then ______.


Value of ∫ `(x^2 + 1)/((x − 1)(x − 2))`dx is ______.


Which partial form corresponds to \[\frac{\mathrm{p}x^{2}+\mathrm{q}x+\mathrm{r}}{(x-\mathrm{a})(x-\mathrm{b})(x-\mathrm{c})}\]?


Which partial form is appropriate for \[\frac{\mathrm{p}x^{2}+\mathrm{q}x+\mathrm{r}}{(x-\mathrm{a})^{2}(x-\mathrm{b})}\]?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×