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Question
Instantaneous acceleration of a particle is correctly expressed as ______.
Options
\[\frac{\Delta\vec{v}}{\Delta t}\] for large Δt
\[\operatorname*{lim}_{\Delta t\to0}\frac{\Delta\vec{v}}{\Delta t}\]
\[\frac{d\vec{x}}{dt}\]
\[\frac{d^2\vec{x}}{dt^2}\]
MCQ
Fill in the Blanks
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Solution
Instantaneous acceleration of a particle is correctly expressed as \[\operatorname*{lim}_{\Delta t\to0}\frac{\Delta\vec{v}}{\Delta t}\].
Explanation:
Instantaneous acceleration is the limiting value of average acceleration when the time interval becomes very small, \[\vec{a}=\lim_{\Delta t\to0}\frac{\Delta\vec{v}}{\Delta t}=\frac{d\vec{v}}{dt}\]. This gives the acceleration at a particular instant.
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