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Question
Insert the symbol ‘=’ or ‘>’ or ‘<’ between the pair of fractions, given below:
`3/7 ... 9/13`
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Solution
`3/7,9/13`
L.C.M. of 7, 13 = 91
∴ `3/7=(3xx13)/(7xx13)=39/91`
and `9/13=(9xx7)/(13xx7)=63/91`
It is clear that `39/91<63/91`
⇒ `3/7<9/13`
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