Question

In which of the circuits shown in Fig. will the galvanometer \(G=100 \Omega\) show no deflection?

Options

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Answer 1

Explanation:

The galvanometer shows no deflection when the Wheatstone bridge is balanced.

According to the Wheatstone bridge principle,

\[ \frac{P}{Q}=\frac{R}{S} \]

For circuit (c),

\[ \frac{2}{4}=\frac{8}{16} \]

\[ \frac{1}{2}=\frac{1}{2} \]

Thus, the Wheatstone bridge is balanced, and no current flows through the galvanometer.

Hence, the galvanometer shows no deflection in circuit (c).