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Question
In which of the following tables x and y vary directly?
(i)
| a | 7 | 9 | 13 | 21 | 25 |
| b | 21 | 27 | 39 | 63 | 75 |
(ii)
| a | 10 | 20 | 30 | 40 | 46 |
| b | 5 | 10 | 15 | 20 | 23 |
(iii)
| a | 2 | 3 | 4 | 5 | 6 |
| b | 6 | 9 | 12 | 17 | 20 |
(iv)
| a | 12 | 22 | 32 | 42 | 52 |
| b | 13 | 23 | 33 | 43 | 53 |
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Solution
\[\text{ If x and y vary directly, the ratio of the corresponding values of x and y remains constant} . \]
\[(i)\]
\[\frac{x}{y} = \frac{7}{21} = \frac{1}{3}\]
\[\frac{x}{y} = \frac{9}{27} = \frac{1}{3}\]
\[\frac{x}{y} = \frac{13}{39} = \frac{1}{3}\]
\[\frac{x}{y} = \frac{21}{63} = \frac{1}{3}\]
\[\frac{x}{y} = \frac{25}{75} = \frac{1}{3}\]
\[\text{ In all the cases, the ratio is the same . Therefore, x and y vary directly } . \]
\[(ii)\]
\[\frac{x}{y} = \frac{10}{5} = 2\]
\[\frac{x}{y} = \frac{20}{10} = 2\]
\[\frac{x}{y} = \frac{30}{15} = 2\]
\[\frac{x}{y} = \frac{40}{20} = 2\]
\[\frac{x}{y} = \frac{46}{23} = 2\]
\[\text{ In all the cases, the ratio is the same . Therefore, x and y vary directly . } \]
\[(iii)\]
\[\frac{x}{y} = \frac{2}{6} = \frac{1}{3}\]
\[\frac{x}{y} = \frac{3}{9} = \frac{1}{3}\]
\[\frac{x}{y} = \frac{4}{12} = \frac{1}{3}\]
\[\frac{x}{y} = \frac{5}{17} = \frac{5}{17}\]
\[\frac{x}{y} = \frac{6}{20} = \frac{3}{10}\]
\[\text{ In all the cases, the ratio is not the same . Therefore, x and y do not vary directly } . \]
\[(iv)\]
\[\frac{x}{y} = \frac{1^2}{1^3} = 1\]
\[\frac{x}{y} = \frac{2^2}{2^3} = \frac{1}{2}\]
\[\frac{x}{y} = \frac{3^2}{3^3} = \frac{1}{3}\]
\[\frac{x}{y} = \frac{4^2}{4^3} = \frac{1}{4}\]
\[\frac{x}{y} = $\frac{5^2}{5^3}$ = \frac{1}{5}\]
\[\text{ In all the cases, the ratio is not the same . Therefore, x and y do not vary directly . } \]
\[\text{ Thus, in (i) and (ii), x and y vary directly .} \]
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