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In the square PQRS, equilateral ΔOPQ is drawn. Prove that ΔOPS ≅ ΔOQR. - Mathematics

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Question

In the square PQRS, equilateral ΔOPQ is drawn. Prove that ΔOPS ≅ ΔOQR.

Theorem
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Solution

Given:

PQRS is a square.

ΔOPQ is equilateral.

To Prove:

ΔOPS ≅ ΔOQR.

Proof:

1. Since PQRS is a square.

All sides are equal.

i.e., PQ = QR = RS = SP.

2. ΔOPQ is equilateral 

⇒ OP = PQ = OQ

3. Consider ΔOPS and ΔOQR.

We need to show they are congruent.

4. In ΔOPS and ΔOQR:

PS = QR   ...(Since PS and QR are sides of the square, they are equal)

OP = OQ   ...(Since ΔOPQ is equilateral, OP = OQ)

∠OPS = ∠OQR   ...(Angles are equal because of the properties of the square and the equilateral triangle sharing vertex O)

5. By the SAS (Side-Angle-Side) congruence criterion. 

ΔOPS ≅ ΔOQR

Hence proved.

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Chapter 8: Triangles - EXERCISE 8A [Page 84]

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B Nirmala Shastry Mathematics [English] Class 9 ICSE
Chapter 8 Triangles
EXERCISE 8A | Q 11. | Page 84
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