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In the given triangle ABC, find a point P equidistant from AB and AC; and also equidistant from B and C. - Mathematics

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Question

In the given triangle ABC, find a point P equidistant from AB and AC; and also equidistant from B and C. 

 

Sum
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Solution

 
Steps of construction:

  1. In the given triangle, draw the angle bisector of ∠BAC.
  2. Draw the perpendicular bisector of BC which intersects the angle bisector at P.
    P is the required point which is equidistant from AB and AC as well as from B and C.
    Since P lies on angle bisector of ∠BAC,
    It is equidistant from AB and AC.
    Again, P lies on perpendicular bisector of BC,
    Therefore, it is equidistant from B and C.
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