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Question
In the given figure, RS is a diameter of the circle. NM is parallel to RS and ∠MRS = 29°. Calculate : ∠NRM
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Solution
Also, RS || NM
∴ ∠NMR = ∠MRS = 29° ...(Alternate angles)
∴ ∠NMS = 90° + 29° = 119°
Also, ∠NRS + ∠MS = 180°
(Pair of opposite angles in a cyclic quadrilateral are supplementary)
`=>` ∠NMR + 29° + 119° = 180°
`=>` ∠NRM = 180° – 148°
∴ ∠NRM = 32°
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